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Volume Calculator

Find the volume of a sphere, cone, cube, cylinder, tank, capsule, spherical cap, frustum, ellipsoid, pyramid, or tube. Mixed length units print a cubic result in each unit.

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V = 4/3 π r³

ExampleSample values — edit any field to see your result.

Results update as you type.

Compute the volume of eleven common solids — sphere, cone, cube, cylinder, rectangular tank, capsule, spherical cap, conical frustum, ellipsoid, square pyramid, and tube. Lengths can be miles, yards, feet, inches, or metric units down to ångströms. Mixed units produce a cubic result in each unit you used.

Common cubic units

Factors use the international foot (1 ft = 0.3048 m exactly), consistent with NIST conversion tables.

UnitCubic metres
1 cubic inch0.000016387064 m³
1 cubic foot0.028316846592 m³
1 cubic yard0.764554857984 m³
1 cubic metre1 m³
1 litre0.001 m³

Examples

Sphere of radius 3 ft

Volume is (4/3) π × 27 = 36π = 113.09733552923 ft³. The same formula with radius 1 m is 4.1887902047864 m³.

Cone with mixed units

Radius 12 in and height 1 ft. In inches both dimensions are 12, so the volume is 1809.5573684677 in³. In feet both are 1, so it is also 1.0471975511966 ft³.

Cube, tank, and pyramid

A 2 ft cube is 2³ = 8 ft³. A 2 × 3 × 4 ft tank is 24 ft³. A square pyramid with base edge 5 ft and height 12 ft is 100 ft³.

Spherical cap from r and R

Base radius 3 ft and ball radius 5 ft give heights 1 ft and 9 ft, so two volumes: 14.660765716752 ft³ and 508.93800988155 ft³. From r = 3 ft and h = 4 ft the ball radius is 3.125 ft and the volume is 90.058989402907 ft³.

Tube of concrete

Outer diameter 3 ft, inner diameter 2.5 ft, length 10 ft is (9 − 6.25) × 10 / 4 = 6.875π = 21.59844949343 ft³.

Formula

Each length is converted into a common unit, the shape formula is applied, and the volume is printed to 14 significant digits. Zero dimensions are allowed and give zero volume; empty or negative values are rejected.

sphere           V = (4/3) π r³
cone             V = (1/3) π r² h
cube             V = a³
cylinder         V = π r² h
rectangular tank V = l × w × h
capsule          V = (4/3) π r³ + π r² h
spherical cap    V = (1/3) π h² (3R − h)
conical frustum  V = (1/3) π h (r² + rR + R²)
ellipsoid        V = (4/3) π a b c
square pyramid   V = (1/3) a² h
tube             V = π (d1² − d2²) l / 4

Spherical-cap conversions when two of the three values are known:

r and R:  h = R ± √(R² − r²)
r and h:  R = (h² + r²) / (2h)
R and h:  r = √(2 R h − h²)
A conical frustum can use either radius as the top or bottom because the volume formula is symmetric. A tube requires its labeled outer diameter to be at least as large as its inner diameter.

What this result does not include

The result is ideal geometric volume from the dimensions entered. Real tanks can have rounded corners, wall thickness, fittings, headspace, or stated usable capacity that differs from outside geometry. Excavation and material purchases also need separate allowances for compaction, spillage, uneven surfaces, and supplier package sizes. Use measured internal dimensions for capacity and the appropriate material calculator for an order estimate.

For a related calculation, use our density calculator.

Measure packed cargo

For repeated cartons or several package sizes, use the CBM Calculator. It totals external package volumes and compares gross with dimensional weight using your chosen divisor. Space estimates remain volume-based and do not guarantee a container fit.

Frequently asked questions

How do I calculate the volume of a sphere?
A sphere of radius r has volume (4/3) π r³. A 3 ft radius is 36π = 113.09733552923 ft³. A 1 m radius is 4.1887902047864 m³. Enter the radius in any of the length units; the result is reported in cubic units of the same kind.
What happens if I mix length units?
Each dimension is converted into every distinct unit you used, then the formula is applied in that unit. A cone with radius 12 in and height 1 ft is 1809.5573684677 in³ and 1.0471975511966 ft³. When every field uses the same unit, you get a single cubic result.
How does the spherical cap solver work?
Enter any two of base radius r, ball radius R, and height h. From r and R there are two heights, h = R ± √(R² − r²), so two volumes (the smaller cap first). From r and h the ball radius is (h² + r²) / (2h). From R and h the base radius is √(2Rh − h²). If all three are filled, r and R are used and h is ignored.
Is the capsule height the full length?
No. Height h is the cylindrical middle only. The two hemispherical ends are added as a full sphere, so V = π r² h + (4/3) π r³. A capsule with r = 1.5 ft and h = 3 ft is 35.342917352885 ft³.
What if the inner tube diameter is larger than the outer diameter?
The entry is rejected because an inner diameter cannot exceed the outer diameter. Correct the labels or measurements, then calculate V = π (d1² − d2²) l / 4. Equal diameters produce zero volume.

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